像瓜子样的曲线

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#http://www.mathcurve.com/courbes2d/clairaut/clairaut.shtmlvertices = 1000t = from 0 to (2*PI)r = 10n = rand2(0.1, 10)p = r*pow(sin(t), n)x = p*cos(t)y = p*sin(t)

面:

vertices = D1:512 D2:200u = from 0 to (2*PI) D1v = from 0 to 50 D2r = 10p = r*pow(abs(sin(u)), v)x = p*cos(u)y = p*sin(u)